python学习源码:采用自定义规定对列表排序

off999 2024-11-01 12:49 30 浏览 0 评论

1、使用lambda表达式指定排序规则

list_dict = [{"name":"无语","python":99,"c":89},
            {"name":"wgh","python":100,"c":80},
            {"name":"琦琦","python":95,"c":97},
            {"name":"明日","python":91,"c":96}]

print("对列表排序前：")
for d in list_dict:
    print(d)
list_dict.sort(key = lambda x :x['python'] ,reverse = True)  # 降序排列

print("对列表排序后：")
for d in list_dict:
    print(d)

对列表排序前：

{'name': '无语', 'python': 99, 'c': 89}

{'name': 'wgh', 'python': 100, 'c': 80}

{'name': '琦琦', 'python': 95, 'c': 97}

{'name': '明日', 'python': 91, 'c': 96}

对列表排序后：

{'name': 'wgh', 'python': 100, 'c': 80}

{'name': '无语', 'python': 99, 'c': 89}

{'name': '琦琦', 'python': 95, 'c': 97}

{'name': '明日', 'python': 91, 'c': 96}

2、采用自定义函数指定排序规则

def rulesort(elem):  # 定义排序规则
    return elem["python"]

list_dict = [{"name":"无语","python":99,"c":89},
            {"name":"wgh","python":100,"c":80},
            {"name":"琦琦","python":95,"c":97},
            {"name":"明日","python":91,"c":96}]
print("对列表排序前：")
for d in list_dict:
    print(d)
list_dict.sort(key = rulesort ,reverse = True)  # 降序排列
print("对列表排序后：")
for d in list_dict:
    print(d)

对列表排序前：

{'name': '无语', 'python': 99, 'c': 89}

{'name': 'wgh', 'python': 100, 'c': 80}

{'name': '琦琦', 'python': 95, 'c': 97}

{'name': '明日', 'python': 91, 'c': 96}

对列表排序后：

{'name': 'wgh', 'python': 100, 'c': 80}

{'name': '无语', 'python': 99, 'c': 89}

{'name': '琦琦', 'python': 95, 'c': 97}

{'name': '明日', 'python': 91, 'c': 96}

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